Page 1 of 1

I_CONSTRAINED_M=2

Posted: Tue Mar 07, 2017 7:00 am
by sd
It is mentioned that the penalty energy decreases with increasing lambda for both I_CONSTRAINED_M=1, and 2 ,
however it appears form me that it is true for only I_CONSTRAINED_M=1 . For I_CONSTRAINED_M=2, penalty energy is directly proportional to lambda ..
Anybody can help?

Re: I_CONSTRAINED_M=2

Posted: Thu Sep 12, 2024 6:55 am
by support_vasp

Hi,

We're sorry that we didn’t answer your question. This does not live up to the quality of support that we aim to provide. The team has since expanded. If we can still help with your problem, please ask again in a new post, linking to this one, and we will answer as quickly as possible.

Best wishes,

VASP